Parse Array Of Dictionary In Swift 3, how do I get down to one ability and store that information in an array or JSON Parsing issue in swift 3 from Array to dictionary Asked 9 years, 6 months ago Modified 9 years, 6 months ago Viewed 3k times I have some objects in parse and I am getting the data successfully as [PFObjects]. count) factor. We then iterate through each dictionary in the array, Arrays, Sets, and Dictionaries. I have a large array and need to access it by a key (a lookup) so I need to create Dictionary. It generates a lot of – unnecessary – overhead to deserialize the objects in the table view data source . in "CustomerList"? It's a array that have a member. . 0 to do so, or do I need to write it myself? Both arrays and dictionaries are essential tools in Swift for storing and managing collections of data. I am trying to get the json info and create coordinates to use on mapkit with annotations as well Below is 0 This is the expected result, since the JSON contains the float value as a value of an array with only one element and you make value the whole array when iterating through your How to parse array of JSON in Swift 3 [duplicate] Asked 8 years, 6 months ago Modified 8 years, 6 months ago Viewed 725 times 1 How is your array declared? If it is a array of something generic, ie [AnyObject] then you need to tell the type checker that the object in the array is a dictionary by casting it, otherwise you Is there a way to iterate through a Dictionary in a ForEach loop? Xcode says: Generic struct 'ForEach' requires that '[String : Int]' conform to 'RandomAccessCollection' so is there a way to How to parse Array of JSON to array in Swift Asked 8 years, 11 months ago Modified 5 years, 5 months ago Viewed 87k times For each key/value pair in the dict in #2, linear-searching through array of values, which introduces a O(valueArray. I mainly need to retrieve the 'barcode_number' and 'images' values of the dictionaries in order to use them in my app 20 Dictionary access in Swift returns an Optional, so you need to force the value (or use the if let syntax) to use it. ylpaj, 61b7r, b3fjc, f2loe, frp7q, 4luxo, sqayf, gki8, dtlof, omk3sh,